6p^2=132

Solution for 6p^2=132 equation:

6p^2=132

We move all terms to the left:

6p^2-(132)=0

a = 6; b = 0; c = -132;
Δ = b2-4ac
Δ = 02-4·6·(-132)
Δ = 3168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3168}=\sqrt{144*22}=\sqrt{144}*\sqrt{22}=12\sqrt{22}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{22}}{2*6}=\frac{0-12\sqrt{22}}{12}
=-\frac{12\sqrt{22}}{12}
=-\sqrt{22}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{22}}{2*6}=\frac{0+12\sqrt{22}}{12}
=\frac{12\sqrt{22}}{12}
=\sqrt{22}
$